Kmap (10mins before exam tricks)

good evening and I'm going to teach you very important topics in digital logic called K map K map and K map is used to simplify simplify Boolean expressions boolean expressions okay, it's very important before we start. k-maps you must know how, what are the formats and how to design the K-map. You forgive the two entries, the format of the K-map looks like these two entries, if you gave a and B, this will represent as a compliment and this is the a this is the complement B and be a complement also the present as 0 this is 1 this is 0 and this is 1 if they give you for the 3 entries if they give us for the 3 entries 3 the entries is this and BN sees a complement and this will be divided into four parts bar B and bar C b bar and C BC and complement BC this will be the format of the kmf that we have given for 3 entries one is another 2 entries is B and C the format is B Bar C bar b Bar C / is also dependent like 0 and 0 B bar and C is dependence like 0 and 1 BC dependent like 1 and 1 and B C different complement S is 0 and 1 and 0 always like 0 and this is 1 if it gave for the 4 inputs , you need to design 4 in 4 matrix 2 3 4 1 2 3 and 4 2 inputs will be the horizontal ones a and B, another 2 will be C and C NTS is When doing C&D, this will be the same.

I will look like a 3 in 3. The format will be the same. A bar B, a bar, a bar, B, A, B and a complement B. Similarly, this will look like a C, body, slash, C, slash d, CD and CD, complement. How will what is promised for the kmf be fulfilled? Perhaps the questions are given in the term of the sum of the product, as question number 12 is given in your task. Sigma of M is equal to 0 3 5, so the 0 3 5 6 8 10 and 14 is not given this is given in those questions 10 2014 10 12 and 14 this is given the questions that this theory means represent as a sorry of the four inputs ABC MD then CN 3 this will be 0 0 and 1 1 I hope you know the boolean expressions and how to design if there are numbers given in decimal format its hexadecimal format how to design in boolean and binary numbers I hope you already know it this way I am smoothly converting this 3 you can write as 0 0 and 1 and 1 similarly this 5 You can write here a b c and d input 4 here so that these two do not become idle B is 4 and this is fine, you can do it as 0 1 0 and 1 , so they can be given in the problems in three formats or they will be given in the form of Sigma of M it is called with this they can give you this plus this 6 can be here 6 you correct it here a b c and d this is the entry 4 you create a bar and this is the you can write here 0 1 1 & 0 okay, you can also write it, it is another entry to go here a b c and for the entry of 3 it would be complemented and you get 1 0 zero and zero, this is 8:12, you can also write it a B C and D four input this will be the inactive one one zero zero plus fourteen major eight plus four plus two fourteen and D completed you go to 1 1 1 and zero so you can see your questions can be given in the three formats or will be given in the sum of the forms of the product 3 5 6 8 10 12 and 14 yes it can be given in the canonical form this is called canonical forms it is given in the same format this is a covalent of this it can be given in the boolean forms 0 0 and 1 and this the conversions that you already know in this are only forgiven, you can convert in the form of the canonical forms and you can also convert in the false boolean if you know the binary how to convert this hexadecimal number see a decimal number in the form of the binary it can be represented in all three formats if you gave ok then all our three are vice versa so if you give us the 4 inputs because you can understand here how it is given in all four formats 3 inputs is what see how to number the camera app, if you provided both inputs you can represent this is 0 1 2 and 3 if you received 3 inputs you can add 0 1 2 and 3 4 5 6 and 7 if you received all 4 inputs you can represent 0 1 2 and 3 4 5 6 and 7 8 9 10 and 11 12 13 14 and 15 this is the representation of any K map for the entries arriving before given the sum of the product forms, so here it is given until the four teens means this is the matrix of the four in a forgiven formula for the four inputs, just as we mentioned in the questions, how many positions are applicable for these expressions, now you have to convert this expression into this big expression of boolean expressions. so we will take the four inputs a B C and D this will be a bar b bar a bar b a b and a P bar C bar d VAR c VAR d CD and CD complement now numbering that you can write in the form that you have in the form of canonical forms any format that can you write I consider forgiving 3 here the three is what shape what step which row and column is this this is a first row third column first row third column okay three you can write the active one now you can think how to take zeros this is 0 0 1 and 1 0 0 1 and 1 a bar b bar and C and D is what animates in the first place 0 0 this is a bar b bar also represents 0 0 0 1 1 0 1 1 in 1 0 this is a pen 0 0 0 1 1 1 and 1 0 so you can see 0 0 and 1 1 which row which column this first I will connect here a bar b Bar C and D a bar b bar C and E a bar b bar a bar b bar a bar b bar and C and E are the first row and the third column now another is the fifth fifth is that you can write a bar BC bar D a bar b c bar d these are the fifth positions that you can verify in the above, that given the numbering here this is the sale , they give us five here you can enter the value of 1 1 6 is this is like west 110 is 1 this is 10 this is 11 so this is you know so is this 11 is 10 is this is - L - L I wish this and 14 this one ends with this one and 14 this one under pairs you put it you write it 0 0 0 you already know if we simplify that kmf first we have to give preference to the octal first you have to give preference to the octal then we will give the word quad and then we will give the pair so you can check it there is what it means to know your character 1 1 1 1 and 1 1 1 1 if you gave it you can make it appear as an octal 1 1 for all the 8 numbers that are given in the 1 and the 1 , but this is what a 1 1 is given and this is 0 and 0, you can't do it doctor, so you'll go for the quadruple.

There's something you know about any quad in the rectum uniforms. Yeah, you can't take the 4. It's diagonal, so there's an octal, these two, and these two. these two these two will be simplified so that you can write as a sea body bar, this is the bar C D, you can take the common bar in D, whoever can take the common theory here will get it, the bar C and I here the I will get is C C bar plus C is 1, so we'll drill it down from the vertical like this for simplicity, you can take the common as a and you look at B plus B bar is 1, you still get a plus this there is none. pair knows any quadrant when you select if this will be the if this will be the one you can do as a pair you can do as a pair you can do as a pair this way 3 but that's what 0 here you can' Do not write any of the pairs, so you have to simplify this to correct a bar b, bar C and D, a bar b, bar y C and E.

Also, this automatically corrects a bar b and C, bar y D, a bar b and c. Before this, you connected this, you corrected a Barbie, a Barbie and a CD bar, a bar, b, c and e, so this will be the simplification of these boolean expressions using the camera application and another method, there are also many methods to simplify , but this. It's one of the best methods to simplify boolean expressions using camera app, it's okay, thanks