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Machst DU diese Fehler auch? – 10 häufige Fehler, Mathe Grundlagen

Jun 08, 2022
Hello dear ones, today I would like to share with you ten common mistakes that occur again and again in math homework. If you don't see an error that happens to you frequently, write to them in the comments and we will make a list. of all the possible errors that occur over and over again we start with the first error here some forget that you have to calculate the point before the dash it is the point from dash rule and you forget it from time to time that's why you like to calculate from the left to the right which is not allowed but many then calculate two to three is five and then multiply that with the 4com then to the result of 20 you can see examples of arithmetic tasks on facebook from time to time but the competitions are not the case you have to pay attention to the point before the dash which means three times here First you have to count four because that's a point every time that would be 12 and then it comes just because it's in the dash are and twelve plus two would then be 14 so that would be the correct result here then the second error occurs with pauses pauses so yes of course there are more errors than just that but that's just an example you think your here is an advantage. i just add all one plus one and two and five plus two equals seven and that's the result unfortunately it's not as good with plus as it is with x this rule really applies but with plus it's like this first of all the denominators they have to be the same here the five and the two are different so first we need a so called captain we need a number that is divisible by five and is also divisible by two which would be 10 for example so now we can divide these the fractions in tenths are expanded, let's do this by looking at five times what is 10, that is, 5 x 2, so we also have to multiply the number here by two once 2002 and the same time here twice what is 10 2 x 5 would be that and once five we have to calculate five and only now the denominators are the same we can add the fractions but darwin cannot simply add everything because he is left with 10 and only the numerators so 2 plus 5 are added and that would be the result ado correct exactly then we come to the third super popular mistake that happens to me over and over again when you jump through a task so fast you forget that a parenthesis is a parenthesis and what for example power is you say yes iks still I'm thinking of everything, and here in the back I just write +3 in mercen los, unfortunately it's wrong because that, it must apply to everything that is in parentheses, which means that not only for the extra: it's out, but also it is necessary for the three days with a minus 3, then you just have to stay focused again and again.
machst du diese fehler auch 10 h ufige fehler mathe grundlagen
Fourth mistake. Thermal baths. Summary. on the idea of ​​just adding it all up somehow i.e. make your own rules and then tell yourself if i want to add something here i just add the numbers seven and four become eleven and also add the tall numbers 2 and 3 for five that doesn't apply that's not a rule because I don't really want to say anything because x2 and the iks raised to three are different so basically they are different families you can call them and you can't go with a family join other families for what seven family members of the iks quadrat family have nothing to do with the four family members of the x3 family that's why in plus you can't really do anything at all and you have to leave it as it is so don't make up any rules just because you can't do anything that will make you negotiate just write something here super happy the following is done yes to The parentheses to the power of two I quadriga just everything in there I calculate x2 and c I calculate four to the power of two so 4 x 4 while 16 done the rule doesn't exist it's super handy and would certainly apply but you actually have to do more here than this do you have to use the genomic formulas or is the part a cutter, so if you keep writing a + b in parentheses so that the square is square that's what's wrong there which it's not but then there's this middle part you tend to forget this 2 x h x b der still goes in and only there in the back then comes this b to the power of two, meaning the parts that are already there that we just had here, but the middle part also needs to go in and so it would be iks to the power of two that but we had b two times then twice x times 4 while 8x needs to be added and then the 4 comes in 2 then the 16 so don't forget here they are between titled between well the following rule applies here so w as many i put up a similar task how is it in my tab community recently and the discussion went crazy here is many have said yes to the power of 2 it means yes everything is squared so as soon as you raise to the power of 2 the result is always positive they say four is coming squares in 16 then it comes out 16 it doesn't because what you just said is only valid if the -4 was actually there for the square in the brackets then this means the -4 is multiplied by itself and -times- you are absolutely right becomes plus and 4 x 4 is 16 but it doesn't suit you here there are no brackets here and if there are no brackets then the brackets are counted first but if there are no parentheses the powers are counted first and then the point comes before the dash, so powers first means that this four to the power of two is stronger than this, right here at the front and you can make it even clearer by saying say what städten are for - anyway, that's just shorthand for al go, that is, for a -1 that is multiplied here, so we could also write this task in such a way that in minus 1 it is multiplied with this power, that is, with this 4 raised to two and there it is, it is even clearer that the powers come before a multiplication, that is, before the point and the line, that means that if we write it like this, 42 is four times four, that is, 16 and if we now multiply the -1 with the 16 we get -16 which can of course abbreviate as i said if you know powers are calculated first then calculate four to the power of two first that has nothing to do here in front it just always draws across and four to two is 16 and that's the result, so always be careful what you say literally in parentheses or just not in the 7th error, I think it's absolute number one.
machst du diese fehler auch 10 h ufige fehler mathe grundlagen

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machst du diese fehler auch 10 h ufige fehler mathe grundlagen...

It's easy with a break like that. I mean that you just shorten it very happily but you also have to see if you can shorten something some would say here because the 4th is there the 4th is also down there I cut it mercilessly no it can't be done here that's why also if I had stopped here once then you can shorten as much as you can but as soon as there is a sum or a difference more or less then there is the mnemonic of differences and sums only stupid short you can't just shorten all four aarau this sums up here you can basically make a bracket around everything that goes together so this part here is one that you can't cut anything like that all it can do is tell you that you can also look at something that can be bracketed so there are similarities between the 4a and the eight of the numbers is not 4 was divided by four and the eight was also divided by four that means you could extract the four from this sum so exclude what bl then 4 divide gone by four is one then an a and in the second part 8 divided by four is 2 so I exclude that here below I leave the 4 times as it is and now it is between uni now they can also shorten it but only if he really does something something and this something counts as a parenthesis so you can shorten the four with the 4 and then there is only this plus two left in the counter and in the denominator use and not the idea that to shorten with the distance because there is an advantage here which means that for you this part here it belongs together and can't erase anything we get to the eighth error the eighth and ninth error go together we must calculate the root of 64 and read that I also comment very often that people are very happy to remember that when taking the square root they came up with two solutions and then they say that the solution here is 8 x 8 x 8 64 and a second solution is st - 8 the only thing is that you have to be careful what you are examining if you only have to calculate the square root of a number then s the result is always positive so the -8 has no place here which is the result of a root square as the positive number so when you take the square root if you must calculate that you always get a positive result what it means is a different question here we come to the ninth error if you have an equation like this here the square equals 64 that's a whole different question so what number squared is 64?
machst du diese fehler auch 10 h ufige fehler mathe grundlagen
Many say, but should I take out the root? Let's see what is the so common mistake here and then take out the root. Sixty is eight. That is my solution. one solution the second solution of this equation is -8 because here the question is yes what number squared is 64 and eight squared and 64 and also -8 squared 64 the detailed explanation if that is not enough i see i just want to remember that to continue we take the root on both sides be clear in any case that means that on one side we write the root of the square and on the other side we also write the root 64 maybe we should calculate the right hand side first because now we know that the square root of 64 is always positive so the square root of 64 is really just eight which we just learned about in the other bug what does it look like on the page about that ixs we don't know anything that ixs might actually be a negative number too because it becomes quadri rdx whatever is ultimately under the root is actually positive so we take the root of a positive number here but we can't just write that then fix is ​​because we don't know each other imagine that a negative number then we would say that the result of a root the task can also be negative, it shouldn't be like that, from a

mathe

matical point of view, one doesn't just write x10 here, but the amount of ex the amount always ensures that even if there was something negative in it the amount ensures that it is positive again so write the amount of -3 for example it's just three the amount of 3 itself if that's already positive stays positive so the quantity always says that the result will be positive and we want that because the roots have to be positive and if we now solve for the quantity so that the number is in it so that e get the quantity eight and then we get two solutions because for this decix there can be eight and the quantity of 8 8 is correct or for the ixs they can actually be -8 too maybe because we just saw that the quantity of -8 makes everything is positive and it's also eight, so that's the

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matical justification.
machst du diese fehler auch 10 h ufige fehler mathe grundlagen
Why do you always remember the following? Because I got the root, I got two solutions, and then we got to the 10th error. It may not happen that often, but it can turn out to be bad. side and then some think I want it to be alone somehow I just divide mercilessly that's why it's dangerous because you can lose solutions because you can't use your xr at all and if you divide by a number it could also happen that then x0 will soon be there dividing something completely unknown i would still have to investigate the case what happens because if i really got zero that is why i would suggest never dividing by euro.
The variable solves that a bit differently than it says. - 3x I calculate so the 4x's are square - the 3x's and on the other side there's just zero so you can add that if you want do the peguform or abc formula but here's a quicker trick to solving this equation because the ixs occurs on both parts here we can factor the ixs that says because there are 4 here there was x2 if we take out one there is only ex in and back here was ex in but we take out so only the three were equal to zero and now we can use the product 0 theorem which says that if we have something equal to zero so here in front is the part is equal to zero so that is equal to zero we already have our solution or this part is equal to zero so fix it: three is equal to zero and if now I got it we put calculating +3 so we have 4x equals here stand three and now divide by four in the last step then we can see that three fourths is another solution so it's just a list solution and three fourths is a solution and this solution I would be here I would talk to you You would have gone down the drain if you had shared here all the time because we can gladly have the participants come through then we would only have 4x standing on one side on the other side only three and you will see that it is really here the second part that you here but what i just lost comes at three quarters the second solution disappeared because you only shared it with iks and zero is not allowed there so you still need to examine them separately there were ten possible errors please write me a comment if it already happened to you please Of course they have. already happened maybe not all but some that just happen very fast if you have selected feel free to write in the comments otherwise until the next video is good

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